Alexander Erler / Arthur Rinderknech Nathaniel Lammons / Jackson Withrow
1 – 2
Finished
S1 5–7 · S2 6–2 · S3 7–10
Sets
| Player | S1 | S2 | S3 | Sets |
|---|---|---|---|---|
| A. Erler / A. Rinderknech | 5 | 6 | 7 | 1 |
| N. Lammons / J. Withrow | 7 | 2 | 10 | 2 |
Match info
- Round
- Round of 16
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